(x-5)^2+3(x-5)+9=0

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Solution for (x-5)^2+3(x-5)+9=0 equation: 



(x-5)^2+3(x-5)+9=0

We multiply parentheses

(x-5)^2+3x-15+9=0

We add all the numbers together, and all the variables

3x+(x-5)^2-6=0

We move all terms containing x to the left, all other terms to the right

3x+(x-5)^2=6

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